My testfile1.txt is just a dummy text file, I have to find at which line and in which column the word "times" occurred.
$ cat testfile1.txt
education times
times of india
happy days happy times
new era new morning
times group
say no to BAD
Here is a one liner:
$ awk 'BEGIN {print "Word \"times\" is found in "}
END {print "Done!!"}
{ for(i=1;i<=NF;i++){
if ($i ~ /times/)
{print "line number "NR,"|column number " i } }
}' testfile1.txt
Output:
Word "times" is found in
line number 1 |column number 2
line number 2 |column number 1
line number 3 |column number 4
line number 5 |column number 1
Done!!
MarRy ChrIstMas to all my readers :-)
Posts
4 comments:
Hello
How do I find the column number and line number in a file for a pattern say "times" in a file where the file data are seperated by comma instead of space ..
Suppose my file.txt contains data as below
output,rsss,rfff,tttt
val1,1,2,3
val2,2,3,4
I want to know the column number of
key word tttt in the above file
Thanks
Sudhakar
@Sudhakar, please use awk FS variable to specify your field separator. e.g.
awk -F ","
Hope this helps.
Thank you Jadu Sakia.
I appreciate your help and personal time.
Thanks again
Hare Krishna !!
Sudhakar
isset() {
eval "case \${${1}++} in ? ) :;; * ) false;; esac"
}
incr() {
eval "$1=\`expr \"\${$1}\" + 1\`"
}
LN=1
unset hdrfutr_eko
srch_word=${1:-'times'}
while IFS= read -r line
do
case $line in
"$srch_word" |\
"$srch_word "* |\
*" $srch_word "* |\
*" $srch_word" )
${hdrfutr_eko+:} echo "Word \"$srch_word\" is found in"
set -f; set X $line; CN=$#; shift
hdrfutr_eko=
while case $# in 0 ) break;; esac; do
case $1 in
"$srch_word" ) echo "line number $LN |column number" "$(expr "$CN" - "$#")";;
esac
shift
done;;
esac
incr LN
done < testfile1.txt
isset hdrfutr_eko && echo 'Done!!'
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