$ cat emails.out
user1@hotmail.com
user2@gmail.com
user3@yahoo.com
user4@rediffmail.com
user5@aolmail.com
Required Output:
-----------------
hotmail
gmail
yahoo
rediffmail
aolmail
Solutions:
Using 2 FS with awk
$ awk 'BEGIN{FS="[@,.]"} {print $2}' emails.out
sed solution:
$ sed 's_\(.*\)@\(.*\)\.\(.*\)_\2_' emails.out
Using cut will be a two way process in this case
$ cut -d@ -f2 emails.out | cut -d. -f1
Similarly, if we do not use two FS in the above awk code, we would need a two way process like this
$ awk -F@ '{print $2}' emails.out | awk -F. '{print $1}'
So to print the UserName($1),SHELL(last field),homedir(6th field) of /etc/passwd file, the sed solution would be:
$ sed 's_\(.*\):\(.*\):\(.*\):\(.*\):\(.*\):\(.*\):\(.*\)_\1,\7,\6_' /etc/passwd
And the awk solution is:
$ awk 'BEGIN {FS=":"; OFS=","; print "UserName","SHELL","homedir"} {print $1,$NF,$6}' /etc/passwd
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