Saturday, August 2, 2008
Print lines with more than two occurrence of a pattern using sed, awk, grep
Input file:
$ cat myfile.txt
"AA "345" SDF"
"BB DERT"
CC"123" "DERA
"12"DD"TYU
ASD""123
Output required:
Print only lines which contain more than two " (double quote)
i.e.
"AA "345" SDF"
CC"123" "DERA
"12"DD"TYU
There are a number of ways to do this:
$ grep '".*".*"' myfile.txt
$ awk -F'"' 'NF>=4' myfile.txt
$ awk '/".*".*"/' myfile.txt
$ sed -n '/".*".*"/'p myfile.txt
$ sed -n '/\("\).*\1.*\1/p' myfile.txt
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© Jadu Saikia www.UNIXCL.com
1 comment:
sed -e 's/"/&/3;t' -e 'd'
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