Lets see how using bash printf command we can format seconds to h:m:s format.
The bash script "convert.sh"
#!/bin/sh
#Convert seconds to h:m:s format
[ -z ${1} ] && echo "Usage: $(basename $0) <seconds>" && exit||secs=${1}
_hms()
{
local S=${1}
((h=S/3600))
((m=S%3600/60))
((s=S%60))
printf "%dh:%dm:%ds\n" $h $m $s
}
_hms ${secs}
Executing:
$ ./convert.sh
Usage: convert.sh <seconds>
$ ./convert.sh 456
0h:7m:36s
The bash one liner for the above script will be:
$ secs=456
$ printf ""%dh:%dm:%ds"\n" $(($secs/3600)) $(($secs%3600/60)) $(($secs%60))
0h:7m:36s
The awk one liner for this:
$ echo - | awk -v "S=456" '{printf "%dh:%dm:%ds",S/(60*60),S%(60*60)/60,S%60}'
0h:7m:36s
Posts
7 comments:
With this reference:
prompt: id=919212
prompt: printf "%02u\n%02u\n%02u\n" $(($id/10000)) $(($id/100%100)) $(($id%100))
Output:
91
92
12
You could also use bit of perl.
perl -e "print scalar(localtime($unixtime))"
@Thanks Ropata
Using %.2d instead of %d will fix the formatting.
To get the 00:00:00 format, use %.2d instead of %d above.
Using %.2d instead of %d will fix the formatting.
secs=${1:-456}
dc -e "
[rldxq]sb
[0r0dldxq]sc
[r1+r60-d60!>a]sa
[n[h:]nn[m:]nn[s]p]sd
0 $secs
d60>claxr0rd60>blaxrldx
"
N.B.: The above involves no division or modulus operations.
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