Directory '/home/user/work/demo/' contains a few regular files and two directories say "part2"(size=41236 KB) and "libs"(size=20620 KB).
$ du ~/work/demo/
41236 /home/user/work/demo/part2
20620 /home/user/work/demo/libs
87640 /home/user/work/demo/
From Linux/UNIX DU(1) command man page:
-s, --summarize
display only a total for each argument.
So, the following command is going to display the total size of the directory '/home/user/work/demo/'
$ du -s ~/work/demo/
87640 /home/user/work/demo/
Now, if you need to find the size of the '/home/user/work/demo/' directory excluding the size of the sub-directories, there is a command line option with DU(1):
-S, --separate-dirs
do not include size of sub-directories
So
$ du -S ~/work/demo/
41236 /home/user/work/demo/part2
20620 /home/user/work/demo/libs
25784 /home/user/work/demo/
Now,
$ du -S --max-depth=0 ~/work/demo/
25784 /home/user/work/demo/
or
$ du -S ~/work/demo/ | awk 'END {print}'
25784 /home/user/work/demo/
1 comment:
You could as well use the summary option -s instead of --max-depth, so `du -sS ~/work/demo` should work. Also, why use `awk END {print }` when `tail -1` is much simpler?
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